Is Commutativity of Addition True for Integers?

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Homework Help Overview

The discussion revolves around proving the commutativity of addition for integers, specifically the statement that for any two integers a and b, a + b = b + a. The original poster references the property holding for natural numbers and attempts to apply it to integers.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the original poster's representation of integers as ordered pairs and whether this assumption is valid. There is a hint provided regarding the definition of addition for these pairs, prompting further exploration of the definitions being used.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the definitions and assumptions involved in the original poster's approach. Some guidance has been offered regarding the need to clarify the representation of integers and the definition of addition being used.

Contextual Notes

There is a suggestion that the original poster may be using a specific presentation of integers that involves ordered pairs of natural numbers, which has not been explicitly stated. This could affect the understanding of the problem and the definitions involved.

iwonde
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Homework Statement


Prove that for any two integers a and b, a+b=b+a. You may use the face that this holds for natural numbers.


Homework Equations





The Attempt at a Solution


a=(x,y), b=(u,v)
x,y,u,v are natural numbers
a+b = (x,y)+(u,v) = (u,v)+ (x,y) = b+a

I'm not sure if my attempt was correct.
 
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iwonde said:
(x,y)+(u,v) = (u,v)+ (x,y)

This step assumes the conclusion. You have to prove it.

Hint: What is the definition of (x,y)+(u,v)?
 
iwonde said:

Homework Statement


Prove that for any two integers a and b, a+b=b+a. You may use the face that this holds for natural numbers.


Homework Equations





The Attempt at a Solution


a=(x,y), b=(u,v)
What do the equations above mean? a and b are integers, not ordered pairs.
iwonde said:
x,y,u,v are natural numbers
a+b = (x,y)+(u,v) = (u,v)+ (x,y) = b+a

I'm not sure if my attempt was correct.
 
Mark44 said:
What do the equations above mean? a and b are integers, not ordered pairs.
I suspect the opening poster forgot to tell us that he's working with a specific presentation of the integers -- represented as the set of ordered pairs of natural numbers modulo an equivalence relation -- along with the definition of + that he's using.

(Of course, maybe that's exactly what you were prompting the opening poster to say -- if so, sorry 'bout that)
 
Nope, I wasn't thinking that at all, so no problem.
 

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