- #1
johne1618
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The cosmological redshift can be understood in terms of time dilation.
In an expanding Universe light travels on a null-geodesic (ds=0) so that:
[tex]
dr = \frac{c\ dt}{a(t)},
[/tex]
where [itex]dr[/itex] is an element of co-moving distance along its path, [itex]dt[/itex] is an element of time and [itex]a(t)[/itex] is the Universal scaling factor.
Thus if a photon is emitted from a co-moving galaxy it starts out with an element of co-moving distance [itex]dr[/itex] given by
[tex]
dr = \frac{c \ \delta t_{em}}{a(t_{em})}
[/tex]
By the time we observe the photon an element of co-moving distance [itex]dr[/itex] is given by
[tex]
dr = \frac{c \ \delta t_{ob}}{a(t_{ob})}
[/tex]
If we equate the two expressions for [itex]dr[/itex] we find an expression for an element of time now when we observe the photon, [itex]\delta t_{ob}[/itex], in terms of an element of time when the photon was emitted, [itex]\delta t_{em}[/itex] :
[tex]
\delta t_{ob} = \frac{\delta t_{em}}{a(t_{em})}
[/tex]
where I take the current scale factor [itex]a(t_{ob})=1[/itex].
Thus if [itex]a(t_{em})=1/2[/itex] when the photon was emitted in the past then one second at time [itex]t_{em}[/itex] is equivalent to 2 seconds now at time [itex]t_{ob}[/itex].
Therefore my clock now is running twice as fast as the same clock at time [itex]t_{em}[/itex].
This interpretation seems at least as valid as the redshift interpretation. Instead of photons being somehow stretched by expanding space as they travel it seems that the passage of time itself is speeding up. I personally could only imagine photon wavelengths being stretched if one had standing waves in an expanding box.
Furthermore if all atomic frequencies are twice as high now as they were at time [itex]t_{em}[/itex] then surely all energies are twice as high now as at time [itex]t_{em}[/itex]?
Thus the redshift that we observe when we observe photons emitted at time [itex]t_{em}[/itex] is due to our energy scale at time [itex]t_{ob}[/itex] being higher than the energy scale at time [itex]t_{em}[/itex].
In an expanding Universe light travels on a null-geodesic (ds=0) so that:
[tex]
dr = \frac{c\ dt}{a(t)},
[/tex]
where [itex]dr[/itex] is an element of co-moving distance along its path, [itex]dt[/itex] is an element of time and [itex]a(t)[/itex] is the Universal scaling factor.
Thus if a photon is emitted from a co-moving galaxy it starts out with an element of co-moving distance [itex]dr[/itex] given by
[tex]
dr = \frac{c \ \delta t_{em}}{a(t_{em})}
[/tex]
By the time we observe the photon an element of co-moving distance [itex]dr[/itex] is given by
[tex]
dr = \frac{c \ \delta t_{ob}}{a(t_{ob})}
[/tex]
If we equate the two expressions for [itex]dr[/itex] we find an expression for an element of time now when we observe the photon, [itex]\delta t_{ob}[/itex], in terms of an element of time when the photon was emitted, [itex]\delta t_{em}[/itex] :
[tex]
\delta t_{ob} = \frac{\delta t_{em}}{a(t_{em})}
[/tex]
where I take the current scale factor [itex]a(t_{ob})=1[/itex].
Thus if [itex]a(t_{em})=1/2[/itex] when the photon was emitted in the past then one second at time [itex]t_{em}[/itex] is equivalent to 2 seconds now at time [itex]t_{ob}[/itex].
Therefore my clock now is running twice as fast as the same clock at time [itex]t_{em}[/itex].
This interpretation seems at least as valid as the redshift interpretation. Instead of photons being somehow stretched by expanding space as they travel it seems that the passage of time itself is speeding up. I personally could only imagine photon wavelengths being stretched if one had standing waves in an expanding box.
Furthermore if all atomic frequencies are twice as high now as they were at time [itex]t_{em}[/itex] then surely all energies are twice as high now as at time [itex]t_{em}[/itex]?
Thus the redshift that we observe when we observe photons emitted at time [itex]t_{em}[/itex] is due to our energy scale at time [itex]t_{ob}[/itex] being higher than the energy scale at time [itex]t_{em}[/itex].
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