Is e^(2lnx) Equal to x^2?

[lemurs]

Ok really dumb one here for you but for the life of me i can't remember.

first
e^(2lnx) is that equal to x^2

like i said brain fart
thanks for the help guys

 

[Midy1420]

yup, e^(2lnx) = e^(ln (x^2)) = x^2

 

[rocomath]

$$e^{2\ln x}$$

$$e^{\ln{x^2}}$$

$$x^2$$