- #1
Calcotron
- 17
- 0
Well, my first question was answered so I figured I would post the second problem I had problems with. It is:
f(x) = lim _{n->\infty}\frac{x^{2n} - 1}{x^{2n} + 1}
Where is f continuous? My first thought is that it is continuous everywhere since I can't find an x value that would make the bottom part of the fraction 0. Isn't that function 1 at for \infty < x \leq-1 or 1 \leq x < \infty and -1 otherwise?
f(x) = lim _{n->\infty}\frac{x^{2n} - 1}{x^{2n} + 1}
Where is f continuous? My first thought is that it is continuous everywhere since I can't find an x value that would make the bottom part of the fraction 0. Isn't that function 1 at for \infty < x \leq-1 or 1 \leq x < \infty and -1 otherwise?
Last edited: