Is f convex on (a,b) if and only if f(y)-f(x)>(y-x)f'(x) for all x, y in (a,b)?

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Homework Help Overview

The discussion revolves around the properties of convex functions, specifically examining the conditions under which a function is considered convex on the interval (a,b). The original poster presents two questions related to the convexity of functions and the implications of their derivatives.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to establish the convexity of a function defined as the maximum of two convex functions and questions the validity of their reasoning regarding second derivatives. They also seek to understand the relationship between differentiability and convexity, specifically whether the inequality involving the derivative holds for all points in the interval.

Discussion Status

Participants are exploring definitions and properties of convex functions. Some participants question the original poster's assumptions about second derivatives and their relevance to convexity. There is an ongoing examination of the definitions and implications of convexity, with no clear consensus yet reached.

Contextual Notes

There is a noted confusion regarding the definition of convexity, particularly in relation to the existence and behavior of derivatives. The original poster's questions reflect a need for clarification on these foundational concepts.

barksdalemc
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Can someone tell me if my logic in answering the following questions is ok:

1. Suppose that f(x) and g(x) are convex on (a,b). Show that the functions h(x)=max[f(x), g(x)] is also convex on (a,b).

-I said that since f and g are convex their second derivatives are not equal to zero in (a,b) and then said since h is the max of f or g, that h also has a second derivative in (a,b) not equal to zero implying it is also convex.

2. Let f be differentiable on (a,b). Show that if f is convex if and only if for all x, y in (a,b): f(y)-f(x)>(y-x)f'(x)

-I'm at a loss on this one.
 
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What is your definition of convex? I guarantee it is not equivalent to "having a second derivative not equal to zero." Not only do convex function need not have even first derivatives, let alone second ones, but those that do certainly can have second derivatives equal to zero, such as any line.
 
ok. the definition states that a curve is convex in a ndb about some x if every point on the curve in the nbd is either above or below the tangent line at x.
 
barksdalemc said:
2. Let f be differentiable on (a,b). Show that if f is convex if and only if for all x, y in (a,b): f(y)-f(x)>(y-x)f'(x)

Rearrange: f(y)[tex]\ge[/tex]f(x)+(y-x)f'(x).
Draw a diagram: Two points (x,f(x)) and (y,f(y)), the horizontal distance between (y-x) and slope at (x,f(x)) is f'(x).
 
Thanks, but it seems like rewording of the definition of convexity. Is that ok?
 
Convex is when the curve is never below any tangent line (it can be above or contained in the tangent).
 

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