Is Fgy the Same as FN in a System with Two Masses and Friction?

[danielsmith123123]

Homework Statement

what is the acceleration and tension of this system
Coefficient of kinetic friction = 0.5
“” “ static “ = 0.6
Mass1 = 20kg
Mass2= 12kg

Relevant Equations

F= ma
Fg = mg

I am just confused on how to find the normal force/ FN of the first object. My classmates are saying Fgy is the exact same as Fn but I don’t get why

Fgy= Fg sin theta
Fgy= (20)(9.81) (sin35)
Fgy= 112.5

Fgy = FN

 

[kuruman]

Your classmates are wrong. Having said that, your expression is incorrect. Draw a force diagram for m1 and you will see why. Hint: sine = opposite/hypotenuse; cosine = adjacent/hypotenuse.

 

[danielsmith123123]

Your classmates are wrong. Having said that, your expression is incorrect. Draw a force diagram for m1 and you will see why. Hint: sine = opposite/hypotenuse; cosine = adjacent/hypotenuse.

Ok, thank you

 

[berkeman]

Is there a diagram that goes with this problem?

 

[kuruman]

Is there a diagram that goes with this problem?

There was, but now it's gone. It showed two masses, m1 on an incline attached to a rope over a pulley to a m2 hanging straight down.

 

[berkeman]

Thanks @kuruman -- I looked in the post history and didn't see a figure. OP must have deleted it after you helped them.