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embphysics
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Homework Statement
The statement that is purported to be true is [itex]\frac{a/b}{c/d} = \frac{ad}{bc}[/itex]
Homework Equations
The Attempt at a Solution
So, I am going along with my proof, and I believe it to be going nicely. However, there is one step that I am unsure of:
[itex]\frac{\frac{a}{b} d}{c} = \frac{\frac{a}{b} d}{c} \cdot d \cdot d^{-1} \Rightarrow \frac{\frac{a}{b} d \cdot d^{-1}}{c d^{-1}} = \frac{\frac{a}{b}}{c d^{-1}}[/itex]. Now, what I want to do is [itex]\frac{\frac{a}{b}}{c d^{-1}} = \frac{\frac{a}{b}}{\frac{c}{d}}[/itex]. But I am having trouble justifying the step [itex]\frac{1}{d^{-1}} =
\frac{1}{\frac{1}{d}}[/itex]
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