Is G a Subgroup of GL[SUB]2[/SUB(Z) Isomorphic to {1,-1,i,-i}?

  • Thread starter Thread starter hsong9
  • Start date Start date
  • Tags Tags
    Isomorphism
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
hsong9
Messages
71
Reaction score
1

Homework Statement


Show that G = {[1 0 [-1 0 [0 -1 [0 1
0 1], 0 -1], 1 0], -1 0]} is a subgroup of GL2[/SUB(Z) isomorphic to {1,-1,i,-i}.

The Attempt at a Solution



I am clearly sure each element in G can be denoted as {1,-1,i,-i}.
(I can explain why {1,-1,i,-i}, but I will not explain at here.)
so G -> {1,-1,i,-i} is a bijection, so isomorphism.

Is it too simple?
 
Physics news on Phys.org
Not every bijection is a group isomorphism. For a map f:G->H, G and H are groups, to be a group isomorphism it needs to be a bijection and have the property that f(ab)=f(a)f(b) for all a,b in G.
You will need to choose your bijection carefully so that this property is satisfied.
 
How do I show that f(ab) = f(a)f(b)..?
Shows everything such that f(1*-1) = f(1)f(-1), f(i*-i)=f(i)*f(-i).. ?
 
Yes, there are 16 different pairs of elements in G.