Is h Continuous and Increasing?

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SUMMARY

The discussion centers on the mathematical function h defined on the interval (0,1) and its properties of continuity and monotonicity. It establishes that if h is continuous on (0,1), then h is necessarily increasing. A counterexample is provided where h is not continuous, demonstrating that continuity is essential for the increasing property. The specific counterexample given is h(x) = 1 for x in (0,1/2] and h(x) = 0 for x in (1/2,1), highlighting the impact of open boundaries on function behavior.

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Homework Statement



We have a worksheet with practice final questions and I'm really stuck on this one on continuity:

Suppose h: (0,1) -> R has the property that for all x in (0,1), there exists a delta>0 such that for all y in (x, x+delta)[tex]\bigcap[/tex](0,1), h(x) <= h(y)

a) prove that if h is continuous on (0,1), then h is increasing.
b) Give a counterexample to show that this need not be true if h is not continuous.

Thanks so much for any help you can provide!

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The Attempt at a Solution





The Attempt at a Solution

 
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Think about h(x)=1 for x in (0,1/2] and h(x)=0 in (1/2,1). Open boundaries make all the difference.
 
Dick's response is to part (b).

For (a), Suppose u< v in (0, 1). If h(u)> h(v), can you get a contradiction to "there exists a delta>0 such that for all y in (x, x+delta)(0,1), h(x) <= h(y)" using the intermediate value property?
 

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