Is it Possible to Construct a Laurent Series of Sqrt(z) About Zero?

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A Laurent series for sqrt(z) about zero is problematic due to the branch point at zero, making it impossible to define the function continuously in an annulus around the origin. The discussion highlights that while a Laurent series typically converges in an annulus, sqrt(z) cannot be expressed this way. Instead, a Puiseux series may be used, although its effectiveness in complex analysis is uncertain. The conversation also raises the question of whether a Laurent series can be constructed for any function around its branch point using similar contour integration techniques. Ultimately, the consensus is that a standard Laurent series cannot be applied to sqrt(z) at zero.
Ancient_Nomad
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Hi,

My mathematics professor said that it is possible to construct a Laurent series of sqrt(z) about zero by integrating over a keyhole contour and then taking the limit R --> 0 where R radius of the inner circle. But I think he is mistaken. I don't understand how it is possible to have a Laurent series about zero, as it is a branch point.

Can someone please clarify this point, and tell me what the series is if such a series exists.

Also, then is it possible to have a laurent series for any function about its branch point by considering a similar contour.

Thanks.
 
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I think you're right; Laurent series converge on an annulus, and square root cannot be defined* on an annulus about the origin.

Square root can be expressed by a (rather boring) Puiseux series, but I'm not sure how well that works complex analytically.


*: I mean in a continuous way, of course.
 

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