mathman said:For the first question, ionization depends on the energy of one photon, not the total energy (photoelectric effect) so the answer is yes if the photon energy is high enough.
I aam not sure what you have in mind for the second question - define light-emitter.
There is no theoretical limit on photon energy - the practical limit is defined by processes which can produce them.Ralphonsicus said:So there is no limit to a photon's energy?
And when I say light emitter, I mean like the equivalent of tungsten in a light bulb. For something to emit x-rays/gamma rays, what temperature must they reach?
Yes, it is possible for a single photon to ionize an atom of Francium. However, the energy of the photon must be equal to or greater than the ionization energy of Francium, which is approximately 3.9 electron volts (eV).
When a photon with enough energy collides with an atom of Francium, it can knock off one of the atom's electrons, resulting in an ionized atom. This process is known as photoionization.
The likelihood of a single photon ionizing an atom of Francium depends on the energy and intensity of the photon, as well as the ionization potential of Francium. Other factors, such as the atomic structure and environment, may also play a role.
Yes, it is relatively rare for a single photon to ionize an atom of Francium. This is because Francium has a high ionization potential and is not commonly found in nature. Additionally, the energy of a single photon is usually not high enough to cause ionization.
The ability to ionize an atom of Francium with a single photon has potential applications in fields such as nuclear physics, atomic clocks, and quantum computing. It can also provide insights into the behavior of atoms at the quantum level.