Is L(x) Continuously Differentiable and Does L(xy) = L(x) + L(y)?

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SUMMARY

The function L(x) defined as the integral from 1 to x of 1/t dt is continuously differentiable over the interval (0, ∞). The derivative L'(x) can be computed using the Fundamental Theorem of Calculus, yielding L'(x) = 1/x. Additionally, it is established that L(xy) = L(x) + L(y) for all x, y in (0, ∞), which can be proven by applying the properties of integrals and the change of variables technique.

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Homework Statement



let L(x)= integral from 1 to x: 1/t dt. Show that L:]0,infinity[--->R is continuously differentiable. show that L(xy)=L(x)+L(y) for all x,y in ]0,infinity[.

hint: let L1(x)=L(xy) and compute L'1(x)



you don't have to solve it for me, just lead me in the right direction please
 
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