Is Log(x) Continuous on the Interval (0, ∞)?

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Homework Help Overview

The discussion revolves around proving the continuity of the function f(x) = log(x) on the interval (0, ∞) using specific properties of logarithms. Participants are exploring the implications of continuity at a specific point and the logarithmic identity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are considering how to apply the continuity at x=1 to extend continuity to the entire interval. There is an attempt to utilize the property log(xy) = log(x) + log(y) in the proof, though some express uncertainty about the validity of their approaches.

Discussion Status

The discussion is ongoing, with participants offering hints and suggestions for manipulating the logarithmic expressions. There is no explicit consensus yet, but several lines of reasoning are being explored.

Contextual Notes

Participants are working within the constraints of a homework assignment that requires a proof using specific properties of logarithms, and there is an emphasis on the epsilon-delta definition of continuity.

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Homework Statement


Prove that f(x)=\log x is continuous on (0, \infty) using that
(1) f is continuous at x=1 and
(2) \log(xy) = \log(x) + \log(y)



Homework Equations


The definition of continuity: for all \epsilon >0, there exists a \delta>0 such that if |x-x_0| < \delta then |f(x) - f(x_0)| < \epsilon.


The Attempt at a Solution


I think I've figured out how to do this using a more standard epsilon-delta proof, but it doesn't really make use of the two facts.
From what I can tell, it seems like you trying to be able to use the continuity at x=1 to "slide" the continuity down to 0 and up to infinity, but I'm not sure how to do this in a valid way. The only way I've managed to use fact 2 is rewrite things like \log x = \log(x \times 1) = \log(x)+\log(1) = \log(x), which hasn't gotten me very far.
 
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Try replacing x_0 with xy for some y.
 
Last edited:
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Look at ##f(x) - f(x_0)##, this becomes ##log(x) - log(x_0)##.
 
hint
log(x+h)-log(x)=log(1+h/x)-log(1)
 

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