Undergrad Lorentz Factor Variant: Derivation & Angle Dependence

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The discussion centers on a derivation of a variant of the Lorentz factor that suggests it depends on the angle of relative movement, with a proposed formula of 1/(sqrt(1-v^2*sin(a)/c^2)+v*cos(a)). However, the traditional Lorentz factor remains 1/sqrt(1-v^2/c^2), which does not vary with angle. Participants clarify that the Lorentz factor is consistent and not influenced by the orientation of velocity in different frames of reference. The thread concludes with a warning against discussing personal theories that contradict established physics. Ultimately, the claim of angle dependence is dismissed as incorrect.
TheSurfers12
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TL;DR
I saw that lorentz factor could change depending of the angle of the relative movement.
I made a derivation of a general transform of the lorentz factor but i still looking in books that the lorentz factor is 1/sqrt(1-v^^2/c^^2) and my derivation is perfectly correct, my result is 1/(sqrt(1-v^^2*sin(a)/c^^2)+v*cos(a)), if we put here 90 degrees we get the classical lorentz factor. Am i right?
 
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What's ##a##? How did you derive this formula?
 
TheSurfers12 said:
Summary:: I saw that lorentz factor could change depending of the angle of the relative movement.

I made a derivation of a general transform of the lorentz factor but i still looking in books that the lorentz factor is 1/sqrt(1-v^^2/c^^2) and my derivation is perfectly correct, my result is 1/(sqrt(1-v^^2*sin(a)/c^^2)+v*cos(a)), if we put here 90 degrees we get the classical lorentz factor. Am i right?
The Lorentz factor depends on the relative speed between two frames of reference, and is always ##\frac{1}{\sqrt{1-v^2/c^2}}##.

The relativistic Doppler effect depends on the angle between the emitted light and the direction of relative motion and the relevant formula involves this angle.
 
Ibix said:
What's ##a##? How did you derive this formula?
(Link to bogus source removed by mentors)
 
Last edited by a moderator:
I'm sorry I asked. Please review the site rules on discussing personal theories.
 
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I think if ##\vec{\beta} = \frac{1}{c}\vec{v}## is the velocity of the primed frame w.r.t. the unprimed frame, then the gamma factor between the frames is$$\gamma^{-1} = \sqrt{1-\vec{\beta} \cdot \vec{\beta}}$$That is in no way dependent on the orientation of ##\vec{\beta}## as measured in the unprimed coordinate system.
 
Thread is now in Moderation pending Mentor review...
 
TheSurfers12 said:
Summary:: I saw that lorentz factor could change depending of the angle of the relative movement.
That’s because you were looking at a (unfortunately familiar) crackpot website, the one you linked to post #4. That website is garbage, and just about nothing it says about relativity can be trusted.

So the answer to your question (does the Lorentz factor depend on the angle?) is no.

This thread is closed because it has started with a false premise.
 
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Ibix said:
I'm sorry I asked. Please review the site rules on discussing personal theories.
Well, we’re glad that you did.
 
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