PhiowPhi said:
@jim hardy made me realize this from my older post.
I remember that thought experiment... the post was titled
Induced current of this conductor?
Maybe you'd put the sketch back up...
to induce Current requires there be a closed loop.
to induce EMF does not.
A single conductor moving through a magnetic field will have a voltage induced in a direction that is perpendicular to both B, and v in the amount BLv.
That word "perpendicular" is more important than it looks.
That voltage comes about because of Lorentz force QV cross B. V and B are vectors.
In that post you refer to, we went ahead and closed the loop so current could flow.
I found a sketch here that might help: http://www.asiaman.net/androo/academics/TAing/phys24/week1/
http://www.asiaman.net/androo/resources/academics/phys24/figures/ClosedLoop-v1-fig1a.png θ
B is going into the paper.
v is to the right.
v cross B points up.
What is the direction of voltage induced in each conductor?
Left vertical conductor will see its internal free charges pushed up , making BLv volts between its ends, i think positive at top.
both horizontal conductors will see their internal free charges pushed up. making B X(thickness of wire) X v volts between top and bottom surfaces of the conductor,
but no voltage between their ends because v cross B points up
Right vertical conductor will have no induced voltage because it is outside the field.
So, what's the sum of the voltages induced in the whole closed loop? The BLv in left wire. Current can flow.
I think if you check up, that formula E = BLv requires mutual perpendicularity.
To account for non-perpendicularity we should multiply by sin(the non-perpendicularangle)
In those horizontal wires, their L and v are not perpendicular they're in same direction. If you multiply by sin(0) you get the correct end to end voltage for them, zero.
Here's another link that at least mentions nonperpendicularity.. when it describes closed loop of a generator see section 22.7
http://www.physics.ohio-state.edu/~humanic/p112_lecture13.pdf
I like to make my mental model and equations agree by at least two different thought trains.
Some people work induction problems by "Flux Cutting", as above where we figured the voltage for each wire in our closed loop as it is "cut" by lines of flux..
Others prefer "Flux Linking" where one calculates the flux enclosed by the loop and its rate of change.
That ohio-state link shows both. methods.
In your loop, enclosed flux is BLx , rate of change of flux is BLdx/dt = BLv, and induced voltage is that many volts per turn.
Hope this helps.
old jim