Is My Servo Motor Calculated Correctly for My Gearbox?

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The discussion centers on calculating the appropriate horsepower (HP) for a servo motor in relation to a gearbox. The user correctly rearranges the formula Torque(in-lb) = HP*63025 / rpm to determine that at 1500 RPM and a stall torque of 92 in-lbs, the motor produces approximately 2.19 HP. This calculation aligns with the gearbox requirement of being rated for at least 2.5 HP. Additionally, the conversion to SI units reveals a power output of approximately 2.2 HP, emphasizing the importance of ensuring the gearbox rating is continuous and suitable for long-term operation.

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SevenToFive
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I am running into a minor snag and would like to know if I am going in the right direction or not. Most gearbox catalogs rate everything for input HP rather than input torque. Would I be able to calculate the motor HP by rearranging the Torque(in-lb) = HP*63025 / rpm, or in this case Torque*rpm/63025=HP
Motor runs at 1500rpm, has a stall torque of 92in-lbs.

92in-lbs*1500rpm/63025 = 2.19HP. So if the gearbox is rated for 2.5HP or greater the motor would be okay to use.
Am I on the right path or lost in the woods?

Thanks to those who reply.
 
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Yes.

Power = torque * angular velocity

But I only work in SI units.

1500rpm = 157 rads/S
92 in-lbf = 10.4 Nm

Power in Watts = 157 * 10.4
= 1633W
= 2.2HP approx.

PS: I don't know what safety margin to use. If the system will be run at 2.2HP continuously make sure the gearbox rating is also "continuous" and the life at that load is predicted to be long enough.
 
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