Is my text book messing wih me again?

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Homework Help Overview

The discussion revolves around finding the coefficient of x^6 in the expansion of the expression (2-3x^2)(1+2x)^8. Participants are examining the steps involved in the expansion and the contributions of different terms to the final coefficient.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the coefficient by breaking down the expression into two parts and applying the binomial expansion. They express confusion regarding the coefficients derived from their calculations.
  • Another participant clarifies that the second term's contribution to x^6 requires considering the x^4 term from the expansion of (1+2x)^8, as it is multiplied by x^2.

Discussion Status

The discussion is active, with participants engaging in clarifying the steps involved in determining the coefficient. Guidance has been provided regarding how to approach the second term's contribution to the overall coefficient.

Contextual Notes

The original poster expresses uncertainty about the coefficients obtained in their calculations, indicating a potential misunderstanding of the expansion process. There is no explicit consensus on the final coefficient yet.

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Here is an example in my book...

Determine the coefficient of x^6 in the expansion of

(2-3x^2)(1+2x)^8


(2-3x^2)(1+2x)^8 = 2(1+2x)^8 - 3x^2(1+2x)^8

The general term in the expansion of (1+2x)^8 is

C(8,k)(2x)^k

Therefore, the term containing x^6 in the expansion of (2-3x^2)(1+2x)^8 is

2(C(8,6))(2x)^6 - 3x^2(C(8,4))(2x)^4 = 2(2^6)(C(8,6))(x^6) - 3(2^4)(C(8,4))(x^6) = 224x^6

The coefficient is 244

Where the heck did these 4's come from? Shouldn't they be 6's or am I missing something?
 
Last edited:
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You're looking for the coefficient of x^6. In the first term, this will be equal to the coefficient of x^6, but the second term is premultiplied by x^2, thus to obtain the coefficient of x^6 in this term, you must look at the term x^4 in the expansion of (1+2x)^8 [since x^2.x^4=x^6]
 
Saved again, thanks Cristo
 
You're welcome.
 

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