Is Reactance the Magnitude of Impedance or Its Complex Part?

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SUMMARY

Reactance is defined as the imaginary part of impedance, represented as |Y|, while the magnitude of impedance is calculated using the formula |Z| = √(R² + X²), where R is resistance and X is reactance. The discussion clarifies that the notation used can be confusing, particularly when distinguishing between the complex components of impedance. Additionally, the phase of a perfect inductor or capacitor is always ±π/2, as derived from the relationship phase = arctan(X/R), where R equals zero for these components.

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  • Understanding of complex numbers in electrical engineering
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JesseC
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My notes say reactance is the magnitude of impedance, so I assume it means this:

[tex]|Z| = \sqrt{X^2 + Y^2}[/tex]

but this is contradicted by numerous internet sources I've read which say that it is the magnitude of the complex part of impedance [tex]|Y|[/tex] . Could someone clarify this?

I'm more inclined to trust the internet given my lecturer is an Astronomer :P
 
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JesseC said:
My notes say reactance is the magnitude of impedance, so I assume it means this:

[tex]|Z| = \sqrt{X^2 + Y^2}[/tex]

but this is contradicted by numerous internet sources I've read which say that it is the magnitude of the complex part of impedance [tex]|Y|[/tex] . Could someone clarify this?

I'm more inclined to trust the internet given my lecturer is an Astronomer :P

The following is the correct form. R is resistance, & X is reactance. BTW, "Y" is admittance, the reciprocal of impedance. Did I help?

[tex]|Z| = \sqrt{R^2 + X^2}[/tex]

Claude
 
Last edited:
Yeah sorry, I've used confusing notation such that Z being a complex number was of the form Z = X+Yj. So the real part X is resistance, and the imaginary part Y is reactance. Clearly modulus of Z is something else altogether, what would its use be?

I have another question while I'm here: Is the phase of a perfect inductor or capacitor always +π/2 or -π/2?

Given that (using your notation) phase is arctan(X/R) and for a capacitor or inductor R = 0, then ±π/2 = arctan(±∞). I never trust myself when it comes to things involving circuits.
 

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