Is Snell's Law Misleading in Refraction Calculations?

Click For Summary

Homework Help Overview

The discussion revolves around the application of Snell's Law in refraction calculations, specifically concerning the transition of light from air into a liquid. The original poster presents a scenario involving indices of refraction and attempts to calculate the unknown refractive index of the liquid based on given angles and the known refractive index of air.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use Snell's Law to find the refractive index of a liquid but questions the validity of their calculations after obtaining an unexpected result. Some participants point out potential errors in the sine values used in the calculations.

Discussion Status

Participants are engaged in identifying errors in the original poster's calculations, particularly regarding the sine values for the angles involved. There is a suggestion to verify the use of a calculator and the importance of correctly identifying units, indicating a productive direction in clarifying the mathematical approach.

Contextual Notes

There is an emphasis on the importance of using correct units and understanding the implications of using a calculator for trigonometric functions, as well as the potential for confusion between degrees and radians.

sinz
Messages
3
Reaction score
0
Snell's law[SOLVED]

1. A ray of light travels from air(which is given to be 1.0003 I also had it be N1) into a liquid. The ray is incident upon the liquid(n2) at an angle of 30 degrees. The angle of refraction is 22 degrees.
Indices of Refraction.
Medium. . . .N
Vacuum...1.00
Air.. . . . ...1.0003
Water...1.33
Ethanol...1.36
Crown Glass.1.52
Quartz...1.54
Flint Glass---1.62
Diamond-----2.42




2. n1 X sinO1= n2 X sin02



3. n1 X sinO1= n2 X sin02 Alright so I am given the O1, O2, N1, but not N2 so I will plug in the numbers.

1.0003 X sin(30)= N2 X sin(22) Then I continue to do the math
1.0003 X -0.988031624 = N2 X -0.00885130929
-0.988328033= N2 x -0.00885130929
so N2= 111.658965


My main problem is that the math doesn't any of the mediums we are given. Did I make a mistake in my work or is the book wrong? I have gone over this many times with myself.
 
Last edited:
Physics news on Phys.org
Those values for sin look very wrong. You should have memorized the sine of 30 degrees, and should have a rough idea about the sine of 22 degrees, so you should be able to recognize that your calculation is wrong.
 
So then it would become
1.0003 x .5 (I knew something looked wrong should not use google calculator ever again.)= n2 X 0.374607
.50015= N2 x 0.374607
Divide by 0.374607
N2= 1.33

Thank you!
 
Don't forego google calculator, just use it correctly! This is a lesson in always writing your units. :smile:

Try asking it "sin 30 degrees".

Without the angle marking, it assumed radians.
 
Oh. Well thank you! Units are very important I just tried google calculator again and wrote radians got the same answer then I did degrees and got .5, Thank you!

Units are important.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
6K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
10K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K