Is Substituting q(t) the Correct Method to Verify a Differential Equation?

Click For Summary

Homework Help Overview

The discussion revolves around verifying whether a function q(t) is a solution to a given differential equation related to circuit dynamics. Participants are exploring the appropriate methods for demonstrating this, particularly in the context of modeling and the implications of the question's wording.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the idea of substituting a proposed solution into the differential equation to verify its validity. There is also mention of deriving the equation from basic circuit principles as a potential approach. Questions arise about the interpretation of the problem and whether the focus should be on proving the formulation of the differential equation rather than finding a solution.

Discussion Status

The discussion is active, with participants providing differing perspectives on how to approach the problem. Some guidance has been offered regarding the interpretation of the question, emphasizing the need to establish the correctness of the differential equation before seeking a solution. There is no explicit consensus yet, as participants continue to explore their understanding of the problem.

Contextual Notes

Participants note that the question may not provide an explicit expression for q(t), leading to discussions about the modeling aspects of the problem. There is also a mention of potential confusion regarding the requirements of the question, indicating that assumptions about the problem setup are being examined.

WWCY
Messages
476
Reaction score
15

Homework Statement



Screen Shot 2017-08-19 at 10.29.14 PM.png

How does one show that q(t) is indeed a solution?

Homework Equations

The Attempt at a Solution


My current idea is that i should come up with any form of solution, like q = Acos(ωt), and slot it in the RHS.
Reason being that if q is indeed a solution, the result of the substitution should look something like the RHS.

Am I missing something? Thanks in advance.
 
Physics news on Phys.org
WWCY said:
Am I missing something?
I would read the question differently than you did.

I think that this is a modeling question, because no expression for ##q## is given yet. What I would do, is show from basic circuit principles that the dynamics of the charge as a function of time is modeled by the given differential equation.

Only in the next step(s), you will then probably be asked to (or led to) find the solution of that DE.
 
Krylov said:
What I would do, is show from basic circuit principles that the dynamics of the charge as a function of time is modeled by the given differential equation.

Thanks for replying!

What did you mean by the above statement? Could you elaborate a little?

Also, I found this bit of proof in relation to these types of DEs in a calculus text:
Screen Shot 2017-08-20 at 3.21.57 PM.png


Could this be another way to approach the problem?
 
WWCY said:

Homework Statement



View attachment 209296
How does one show that q(t) is indeed a solution?

Homework Equations

The Attempt at a Solution


My current idea is that i should come up with any form of solution, like q = Acos(ωt), and slot it in the RHS.
Reason being that if q is indeed a solution, the result of the substitution should look something like the RHS.

Am I missing something? Thanks in advance.

No, as Krylov has said, you have mis-read the question. The question said "Show that ##q(t)## obeys ... " so it is not asking for a solution of a differential equation. It is asking you to prove that the given differential equation is a correct formulation.

The point is: first you get the correct DE; then you worry about solving it.
 
Ray Vickson said:
No, as Krylov has said, you have mis-read the question. The question said "Show that ##q(t)## obeys ... " so it is not asking for a solution of a differential equation. It is asking you to prove that the given differential equation is a correct formulation.

The point is: first you get the correct DE; then you worry about solving it.

Hi, thanks for replying.

So what you mean is that I should first derive the equation? (Apologies if I was slow to understand this)

But say I've already derived the equation, do I still need to check whether or not it's "correct" by substituting q = qp + qc?

Thank you.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
9K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
9K
  • · Replies 9 ·
Replies
9
Views
3K