Is the Alternative Method for Integration by Parts Simpler?

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Discussion Overview

The discussion revolves around the integration by parts formula, specifically questioning the traditional form of the formula and proposing an alternative method. Participants explore the implications of using this alternative approach in terms of simplicity and ease of calculation.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose an alternative method for integration by parts, suggesting that replacing v' with v and v with ∫vdx simplifies the process.
  • One participant argues that their proposed method allows for straightforward calculations without the need to think backwards, contrasting it with the traditional formula.
  • Another participant provides an example using the integral ∫xe^xdx to illustrate their approach, claiming it is simpler than the conventional method.
  • Concerns are raised about the placement of the constant of integration in the proposed method, with participants noting that it can lead to confusion if not handled correctly.
  • Some participants express a belief that the traditional form is used for the sake of mathematical rigor, despite finding it more complicated.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the superiority of either method. There are competing views regarding the simplicity and effectiveness of the traditional integration by parts formula versus the proposed alternative.

Contextual Notes

Participants highlight potential confusion regarding the constant of integration in their alternative method, indicating that this aspect may require careful consideration. The discussion does not resolve the implications of using the alternative method in various contexts.

DivergentSpectrum
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I have a question why everyone says
∫uv' dx=uv-∫u'v dx
why don't they replace v' with v and v with ∫vdx and say
∫uv dx=u∫vdx-∫(u'∫vdx) dx

i think this form is a lot simpler because you can just plug in and calculate, the other form forces you to think backwards and is unnecessarily complicated.
 
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DivergentSpectrum said:
I have a question why everyone says
∫uv' dx=uv-∫u'v dx
why don't they replace v' with v and v with ∫vdx and say
∫uv dx=u∫vdx-∫(u'∫vdx) dx

i think this form is a lot simpler because you can just plug in and calculate, the other form forces you to think backwards and is unnecessarily complicated.
Show us an example of how this would work, with say ##\int xe^xdx##.
 
u=x
v=e^x
∫(x*e^x)dx=x*∫e^xdx-∫e^xdx
=xe^x-e^x+c

right? its a lot simpler than thinking backwards and doing the substitution i always have to right it down my way cause the other way is too complicated.

edit: i just noticed that perhaps some people may be confused as to where the constant of integration goes
∫(x*e^x)dx=x*∫e^xdx-∫e^xdx
∫(x*e^x)dx=x*(e^x+c)-(e^x+c)
this would be wrong but as long as you keep in mind that the constant cooresponds to a vertical translation you can't go wrong. so I am guessing for the sake of mathematical rigor they use the other form?
 
Last edited:
DivergentSpectrum said:
u=x
v=e^x
∫(x*e^x)dx=x*∫e^xdx-∫e^xdx
=xe^x-e^x+c

right?
You checked it, didn't you?
DivergentSpectrum said:
its a lot simpler than thinking backwards and doing the substitution i always have to right it down my way cause the other way is too complicated.
I think of it like this: ∫v du = uv - ∫u dv. That's not very complicated.
DivergentSpectrum said:
edit: i just noticed that perhaps some people may be confused as to where the constant of integration goes
∫(x*e^x)dx=x*∫e^xdx-∫e^xdx
∫(x*e^x)dx=x*(e^x+c)-(e^x+c)
Ignore it in your intermediate work. Just add it at the end.
DivergentSpectrum said:
this would be wrong but as long as you keep in mind that the constant cooresponds to a vertical translation you can't go wrong. so I am guessing for the sake of mathematical rigor they use the other form?
 

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