Is the Diffraction Grating's Line Count Accurate?

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SUMMARY

The discussion centers on verifying the accuracy of a diffraction grating's line count, specifically a grating claiming 13500 lines per inch (5315 lines/cm). Using a 650 nm red laser, the user measured the distance between the central maximum and the first-order maximum (m=1) to be 4.1 cm, with the grating positioned 30 cm away. Calculations using the grating equation revealed a calculated line count of 2080 lines/cm, indicating a significant discrepancy from the claimed value. The user seeks confirmation of their calculations and potential errors in their methodology.

PREREQUISITES
  • Understanding of the grating equation: d sin(theta) = m(lambda)
  • Familiarity with diffraction grating concepts and measurements
  • Knowledge of basic trigonometry and geometry
  • Experience with laser wavelength measurements
NEXT STEPS
  • Review the derivation and application of the grating equation in optics
  • Learn about the impact of measurement errors in diffraction experiments
  • Investigate methods for accurately measuring angles in diffraction setups
  • Explore the relationship between wavelength and line density in diffraction gratings
USEFUL FOR

Physics students, optical engineers, and anyone involved in experimental optics or diffraction analysis will benefit from this discussion.

Grebulous
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This is an intro lab-based question.

Homework Statement


I took a 650 nm red laser and shined it through a diffraction grating that claimed it had 13500 lines/inch, which comes to 5315 lines/cm in civilized people units. The grating was placed 30 cm away from a piece of paper on the wall. The distance between the central maximum (m=0) and the m=1 maximum was measured to be 4.1 cm. I'm trying to verify that the number of lines per cm is in fact around 5315.

Homework Equations


The grating equation, d sin(theta) = m(lambda)

The Attempt at a Solution


m=1 for the first maximum, and rearranging the equation, d = lambda/sin(theta). d equals the spacing between each slit, which is just 1/N, where N is the number of lines per cm. sin(theta) is 4.1/sqrt(30^2 + 4.1^2) = 0.1354. So, N = sin(theta)/lambda = 0.1354/(6.5 x 10^-5 cm) = 2080 lines/cm, to 3 s.f.

I find that answer odd - did I make some really basic mistake, or does the grating really have 2.5 times fewer lines than it claims it does? If I were to go the other way and assume N was right, I'd get an ultraviolet wavelength, and I double-checked my measurements. Can anybody spot my goof?
 
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Your calc looks good.
 

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