Is the Electric Field Calculation Consistent with the Potential Result?

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SUMMARY

The discussion centers on the consistency between electric field calculations and potential results in electrostatics, specifically addressing the formula for the electric field \( E_{-}=\frac{|\pi|}{2\epsilon_0} \). Participants clarify that the symbol \( \pi \) was a misinterpretation of the surface charge density \( n \). The relationship between the variables \( d \) and \( d' \) is established as \( d=d'+R \), where \( R \) is the radius of the solid sphere. The integration of the electric field \( E \) to derive the potential \( V \) is confirmed to align with textbook results, affirming the correctness of the calculations presented.

PREREQUISITES
  • Understanding of electrostatics principles
  • Familiarity with electric field and potential relationships
  • Knowledge of integration techniques in physics
  • Concept of surface charge density
NEXT STEPS
  • Study the derivation of electric fields from surface charge distributions
  • Learn about the relationship between electric field and potential in electrostatics
  • Explore integration methods for calculating potential from electric fields
  • Investigate common mistakes in interpreting physical symbols in equations
USEFUL FOR

Students and educators in physics, particularly those focusing on electrostatics, as well as anyone involved in solving problems related to electric fields and potentials in solid spheres.

Cactus
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Homework Statement
Hey, I just wanted to post these two questions to check whether the answers I've gotten are correct, as I have no real way of checking if what I've done is correct (This is for parts c and d of the attached question)

For c, would the electric field along the z axis just be the superposition of the field from a negatively charged plate plus the field of a positively charged sphere (as along the z axis the field lines are parallel to the axis)

Likewise, for d, would this be the correct way to go about solving for capacitance given the formula for potential, as I can't see any other way to cancel the Vo and express capacitance purely in geometric terms
Relevant Equations
Capacitance = Charge/Potential Difference
Electric Field of an Infinite Plate
Electric Field of a Sphere
Question
1566623180424.png


Part C
1566623135172.png


Part D
1566623156411.png
 
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at part C How you can write $$ E_{-}=\frac{|\pi|}{2\epsilon_0} $$ and what is $$ \pi $$
 
Masano Hutama said:
at part C How you can write $$ E_{-}=\frac{|\pi|}{2\epsilon_0} $$ and what is $$ \pi $$
ah that's not pi its just a badly written n as in surface charge density
 
Part c must be correct from you, only thing I have to say is that the d in the book scheme and the d in your notes are different. If I call d' the d of your notes and simply d the d from your book it is

d=d'+R, where R is the radius of the solid sphere,

and having that in mind, the result you get for electric field E in part c seems to be in agreement with the result for potential V that is given by the book(Just integrate your E-field and you ll get the V as presented by the book, we know that ##V=\int Edr##).

Part d also seems correct.
 
Delta2 said:
Part c must be correct from you, only thing I have to say is that the d in the book scheme and the d in your notes are different. If I call d' the d of your notes and simply d the d from your book it is

d=d'+R, where R is the radius of the solid sphere,

and having that in mind, the result you get for electric field E in part c seems to be in agreement with the result for potential V that is given by the book(Just integrate your E-field and you ll get the V as presented by the book, we know that ##V=\int Edr##).

Part d also seems correct.
Yeah I realized my mistake with the d and d' after posting this and fixed that, but thanks for the reply and confirmation on answers. I've also had a friend finish this question now and got the same answers so fingers crossed they're right
 

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