Is the Equation x^4 + y^4 - xy^2 = x^2y Solvable or Simplifiable?

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Homework Help Overview

The discussion revolves around the equation x^4 + y^4 - xy^2 = x^2y, with participants exploring its solvability and potential simplifications. The subject area includes algebraic manipulation and polynomial equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about the nature of the problem, questioning whether it can be solved or simplified due to the presence of unlike terms. Some inquire about the original context of the equation and whether it was presented in a specific way in class.

Discussion Status

There is an ongoing exploration of the equation's properties, with some participants suggesting possible solutions by inspection. Others are questioning the clarity of the problem and the intended goal of the discussion, indicating a lack of consensus on how to proceed.

Contextual Notes

Participants note that the equation was written on a board by a classmate and is not part of any formal homework assignment. There is also mention of potential solutions found by inspection, but the overall context remains unclear.

kyphysics
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Homework Statement


x^4 + y^4 - xy^2 = x^2y

Homework Equations


None. However, I'm using "^" to represent an exponent operation.

The Attempt at a Solution


Not sure. That's why I'm asking. It just feels to me that everything is an unlike term and thus you can't do anything.

Is that correct here? Thanks for the help everyone!
 
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How do you mean 'solved'? Do you mean finding roots?
Is this the whole question as given to you? If not, please post the original question.
 
You can do a little factoring by subtracting a convenient amount from each side, but without knowing what your goal is I'm not sure what benefit would result.
 
kyphysics said:

Homework Statement


x^4 + y^4 - xy^2 = x^2y

Homework Equations


None. However, I'm using "^" to represent an exponent operation.

The Attempt at a Solution


Not sure. That's why I'm asking. It just feels to me that everything is an unlike term and thus you can't do anything.

Is that correct here? Thanks for the help everyone!

If I understand what you wrote, it looks like x=y=1 is a solution by inspection. Where is the equation from?
 
berkeman said:
If I understand what you wrote, it looks like x=y=1 is a solution by inspection.
As are x = 0, y = 0.
 
Here's a graph, for what it's worth. I've included ##y=\pm x## in the picture:
graph.jpg

Click on it for a better view.
 
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Very Cool :-)
 
haruspex said:
How do you mean 'solved'? Do you mean finding roots?
Is this the whole question as given to you? If not, please post the original question.

First, Merry Christmas! lol.

I just logged back in here after getting bored today and wanting to catch up on my threads! Sorry it's taken so long, but thanks for the answers!

As for the "original question," this is what was written on the board of our class by some girl doing some stuff after class. It's not from any worksheet I had from the class (I even doubled-chcked), but was just a random "problem" I saw on the board and was puzzled by when I glanced at it and thought I'd jot it down.

My question is whether anything can be done arithmetic-wise to combine what seem like unlike terms? And also, can the equation be solved above in any way?
 

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