Is the Function f(x)=1/(1-1/x) Defined at x=0?

  • Thread starter Thread starter foxjwill
  • Start date Start date
  • Tags Tags
    Value
Click For Summary
SUMMARY

The function f(x) = 1/(1 - 1/x) is not defined at x = 0 due to division by zero in the denominator. The discussion confirms that 1/0 is undefined, leading to the conclusion that f(0) does not exist. Participants unanimously agree on this mathematical principle, emphasizing the importance of recognizing undefined expressions in calculus.

PREREQUISITES
  • Understanding of basic algebraic functions
  • Knowledge of limits and continuity in calculus
  • Familiarity with the concept of division by zero
  • Basic mathematical notation and terminology
NEXT STEPS
  • Study the concept of limits in calculus to understand behavior near undefined points
  • Explore the implications of division by zero in various mathematical contexts
  • Learn about piecewise functions and how they handle discontinuities
  • Investigate the definition of functions and their domains in algebra
USEFUL FOR

Students studying calculus, mathematics educators, and anyone seeking clarity on function definitions and undefined expressions.

foxjwill
Messages
350
Reaction score
0
[SOLVED] value of 1/(1-1/0) at 0

Homework Statement


Is the function
[tex]f(x)=\frac{1}{1-\frac{1}{x}}[/tex]​
defined at [tex]x=0?[/tex]

Homework Equations


The Attempt at a Solution


Since we have division by zero in the denominator, I'm assuming that it isn't. Am I correct?
 
Physics news on Phys.org
I would agree.
 
Yes, 1/0 is NOT defined. You don't have to "assume" anything!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
8
Views
2K
Replies
4
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K