Is the Graph of a Continuous Function Closed in R^2?

[jaci55555]

The graph of a continuous funtions (R -> R) is the subset G:={(x, f(x) | x element of R} is a subset of R^2. Prove that if f is continuous, then G is closed in R^2 (with euclidean metric).


I know that continuity preserves limits, so x_n -> x in X means f(x_n-> y in Y.
and for all A element of R^2 - G there exists r > 0 st B(a, r) subset of R^2 - G.I know that if R^2 - G is open then G is closed.


What is the connection between limits and the open ball B? I think that might be the way...

 

[micromass]

the following characterization might be useful:

A subset F of a metric space X is closed iff for all sequences (x_n) in F which converges to a certain x in X, it holds that x is in F.