Is the Integral of (sinx)/(1+cos^2(x)) convergent or divergent?

Click For Summary
SUMMARY

The integral of (sinx)/(1+cos^2(x)) from 0 to infinity is convergent, with the solution yielding a value of π/4. The convergence can be established using the comparison test, as the integrand behaves similarly to sin(x) for large x. The antiderivative can be found using the substitution u=cos(x), which simplifies the evaluation of the limit as L approaches infinity.

PREREQUISITES
  • Understanding of improper integrals
  • Familiarity with the comparison test for convergence
  • Knowledge of basic trigonometric identities
  • Experience with integration techniques, specifically substitution
NEXT STEPS
  • Study the comparison test for improper integrals
  • Learn about trigonometric substitution in integration
  • Explore the properties of the sine function in integrals
  • Review techniques for evaluating limits of integrals as bounds approach infinity
USEFUL FOR

Students in calculus, mathematicians analyzing improper integrals, and anyone seeking to understand convergence in integral calculus.

tbone413
Messages
7
Reaction score
0

Homework Statement


State whether the problem is convergent or divergent and if its convergent solve the integral. Integral from 0 to inf of (sinx)/(1+cos^2(x))dx


Homework Equations


there isn't really an equation for this, I don't think.


The Attempt at a Solution



Im not really sure how to even start this problem. I know it converges, and I know the answer is pi/4 (the book has the answer) but I am stuck on how to figure out that it A) converges and B) how to solve it.

*I know there are several tests you can use to test for convergence (ratio test, p test, etc.) but I am not sure which one applies here.
 
Physics news on Phys.org
It doesn't converge. Find the antiderivative, use u=cos(x). Evaluate it between 0 and L and then let L->infinity. Does it approach a limit?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K