Is the Internal Resistance of the Voltmeter Accurate in Series Circuit?

[kliker]

Homework Statement

a resistor of 600 Ω and one of 400 Ω are connected in series and their combination is being supplied by 90 V. A voltmeter that is connected on edge of the resistor of 600 Ω shows 60 V. a) what's the internal resistance of the voltmeter.

The Attempt at a Solution

i found the real V in the resistor of 600 V which is 54 V. But the voltmeter shows 60 V. Now I don't know how is this possible

if they are in parallel could we just find the Rtot that will be Rv* Rs/(Rv+Rs) and then say I = V/R

and from this equation find the Rv? but i find false results using this method, the book says 3000 Ω

 

[ehild]

The voltmeter reads 50 V if its internal resistance is 3000 ohm. 60 V is impossible.

ehild

 

[kliker]

The voltmeter reads 50 V if its internal resistance is 3000 ohm. 60 V is impossible.

ehild

hm, so the book has it wrong?

Im using the university physics by Hugh D. Young it's in chapter 27

never mind, let's suppose that it reads 50, how can I find the resistance of the voltmeter? There isn't any method inside the book, and our teacher never explained us anything like that, I'm just curious how this can be solved

thanks in advance

 

[ehild]

Draw the circuit diagram first. Show me, please.

ehild