Calculating voltmeter resistance in DC circuit

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Homework Help Overview

The problem involves calculating the resistance of a voltmeter connected across a resistor in a DC circuit. The circuit consists of a 228-Ω resistor and a 586-Ω resistor in series with a 90.0-V power supply, and the voltmeter reads 24.0 V across the 228-Ω resistor.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of Ohm's law and the concept of equivalent resistance in series circuits. There are questions about how to determine the total current and the impact of the voltmeter on the circuit. Some suggest using Kirchhoff's loop equations to analyze the circuit further.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants offer guidance on calculating equivalent resistance and suggest methods to relate the voltmeter's resistance to the circuit parameters. There is no explicit consensus on the best approach yet.

Contextual Notes

Participants note that the voltmeter typically does not disturb circuit parameters, but its presence may affect current distribution. There is also mention of the need to calculate total resistance with and without the voltmeter.

ztalira
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Homework Statement


initial problem: A 228 −Ω resistor and a 586 −Ω resistor are connected in series across a 90.0−V line.
A voltmeter connected across the 228 −Ω resistor reads 24.0 V . Find the voltmeter resistance.
For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?

Homework Equations


V=IR
1/Req=1/R1 +1/R2

The Attempt at a Solution


For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?
 
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The total current is going to be given by V = IR

They give you the total voltage and they give you the resistors. To find the total resistance you have to find the equivalent resistance. The resistors are connected in series, not in parallel, so what does that tell you about how to calculate the equivalent resistance?

Once you solve for the equivalent resistance and find the total current, you can use Ohm's law again and find the resistance with the voltmeter. The resistance of the voltmeter itself will then be the difference between the value of the resistance with it and the value without it.
 
ztalira said:
For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?

normally a voltmeter does not disturb a circuit parameters - but suppose it draws a current say( Iv) then the current in 228 ohm resistance will be reduced by Iv so you have two loops one smaller one through voltmeterand the 228 ohm. a larger loop is current flowing through the two resistances- one can apply Kirchhoff's loop equations to relatecurrent and voltage and resistances. that should solve your problem
 
Calc.JPG
https://www.physicsforums.com/attachments/96995
Sim.JPG
 
The first calculation is simply a voltage divider where you can determine the resulting resistance after puting the voltmeter across R1 => Rx.
Then take Rx and calculate back using the formula you use when you have two resistors in parallel and want to know the total resistance.
you don't need a current to find Rv.
except you have to calculate them. then just use the total resistance without the voltmeter and then with the voltmeter...where R1 changes to Rx.

br Chris
 

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