Is the Law of Motion Explanation Correct?

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Homework Help Overview

The discussion revolves around the application of the laws of motion in the context of friction and the forces acting on a block. Participants are examining the conditions under which the block begins to move, particularly focusing on the relationship between applied force, frictional force, and the angle of inclination.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the validity of the frictional force expression given in the attachment, particularly the assumption that the maximum static friction force is equal to \(\mu mg\) without vertical motion being involved. There are discussions about the role of the angle of inclination and how it affects the normal force and friction.

Discussion Status

There is an active exploration of different interpretations regarding the forces at play. Some participants express confusion about the relationship between the applied force and the frictional force, while others attempt to clarify the conditions under which the block will move. Guidance has been offered regarding the conditions necessary for movement, but no consensus has been reached.

Contextual Notes

Participants note the lack of vertical motion in the problem setup, which raises questions about the assumptions made regarding the normal force and friction. There is also mention of an attachment that contains relevant diagrams or equations that are central to the discussion.

snshusat161
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View this attachment and tell me whether it is correct or not? It is written there that to move the block we need F Sin[tex]\theta[/tex] > [tex]f_s[/tex]. I agree but then they have given the value of [tex]f_s[/tex] equal to [tex]\mu[/tex]mg. How can it be possible as we don't have any vertical motion.
 

Attachments

  • wrong concept.jpg
    wrong concept.jpg
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Frictional force is a self adjusting force which depends on the normal reaction. The maximum friction force ( when the object starts moving) is mu*mg. This frictional froce acts in the opposite direction of the relative motion of the two objects.
 
wow, but I'm already familiar with this concept. Please have a look on attachment
 
snshusat161 said:
wow, but I'm already familiar with this concept. Please have a look on attachment
How can it be possible as we don't have any vertical motion
In this problem there is no question of vertical motion.
 
You are not understand what I mean to say or may be you are acting too lazy to look on the picture I've given.
 
I agree but then they have given the value of LaTeX Code: f_s equal to LaTeX Code: \\mu mg. How can it be possible as we don't have any vertical motion.
I have gone through the attachment and your above statement. In the attachment there no suggestion of vertical motion.
Actually the expression should be
fs = mu[Fcos(theta) + mg], because R = mg + f*cos(theta)
 
yes, that's what I wanted to confirm. Thanks
 
Can you tell me what should be minimum angle if it derived correctly.
 
And see this, if the frictional force is greater than the applied force then how can a body move. What rubbish they have printed on the book.
 

Attachments

  • wrong concept 2.jpg
    wrong concept 2.jpg
    24.8 KB · Views: 399
  • #10
In the first problem, if theta is zero, the block will not move in the horizontal direction. Net normal reaction is mg + F. As the angle increases, f*sin(theta) increases and R decreases.
Body starts moving when Fsin(theta) = mu[mg + Fcos(theta)].
The formula derived in the attachment is true when the object placed on the horizontal plane starts moving when the angle of inclination of the plane to the horizontal satisfies the relation mu = tan(theta)
 

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