Is the Lie derivative a tensor itself?

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SUMMARY

The Lie derivative is confirmed to be a tensor itself, as established in discussions surrounding its application in General Relativity. Specifically, the Lie derivative acts on vector fields and tensors, maintaining linearity in both arguments. The general expression for the Lie derivative of a tensor with respect to a vector field can be derived using coordinate transformations, demonstrating its tensorial nature. This is exemplified by the formula for a vector field, which shows that the Lie derivative retains the properties of a tensor.

PREREQUISITES
  • Understanding of vector fields in differential geometry
  • Familiarity with the concept of derivatives in the context of tensors
  • Knowledge of coordinate transformations in tensor calculus
  • Basic principles of General Relativity
NEXT STEPS
  • Study the properties of the Lie derivative in detail
  • Explore the relationship between Lie derivatives and covariant derivatives
  • Investigate the implications of torsion on the Lie derivative
  • Read about applications of Lie derivatives in physics, particularly in General Relativity
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Students and professionals in mathematics and physics, particularly those studying differential geometry, General Relativity, and tensor calculus.

spinless
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Hi everyone!

A few days ago in General Relativity class, the professor introduced the concept of Lie derivative and at the end he mentioned that the Lie derivative was a tensor itself. I've been looking everywhere, but I only find how it acts on vectors, tensors, etc. Does anyone know of any book/article/website that mentions this idea?

Thank you very much in advance!!
 
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Here are some definitions:
https://www.physicsforums.com/insights/pantheon-derivatives-part-iv/#Lie-Derivatives

If ##X,Y## are vector fields, then ##\mathcal{L}_X(Y)=[X,Y]## which is again a vector field. ##\mathcal{L}## is linear in both arguments, so you may consider it a tensor. How it acts can be seen in the article I linked to.

Every derivative is a directional derivative. It measures variation in that direction. There are three main parameters: function, direction, and location. All of them can be the variable that results in different quantities: a number, a function, or even a field of directions. We abstract from function and location and consider directions alone in the case of vector fields.
 
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Moderator's note: Thread moved to the Differential Geometry forum.
 
spinless said:
Hi everyone!

A few days ago in General Relativity class, the professor introduced the concept of Lie derivative and at the end he mentioned that the Lie derivative was a tensor itself. I've been looking everywhere, but I only find how it acts on vectors, tensors, etc. Does anyone know of any book/article/website that mentions this idea?

Thank you very much in advance!!
The Lie derivative of a tensor is a tensor. Just like the derivative of a functions is a function.
 
spinless said:
Hi everyone!

A few days ago in General Relativity class, the professor introduced the concept of Lie derivative and at the end he mentioned that the Lie derivative was a tensor itself. I've been looking everywhere, but I only find how it acts on vectors, tensors, etc. Does anyone know of any book/article/website that mentions this idea?

Thank you very much in advance!!
You can find the general expression for the Lie derivative of a tensor with respect to some vector field ##\xi##. Just apply the definition, and perform a general coordinate transformation to see whether you get inhomogenous terms. E.g., for a vector field ##V## you obtain in component form

##L_{\xi} V^{\mu} = \xi^{\lambda} \partial_{\lambda}V^{\mu} -V^{\lambda}\partial_{\lambda}\xi^{\mu}##

If you're dealing without torsion, you can actually show that this equals

##L_{\xi} V^{\mu} = \xi^{\lambda} \nabla_{\lambda}V^{\mu} -V^{\lambda}\nabla_{\lambda}\xi^{\mu}##

Similar arguments hold for Lie derivatives of general tensor fields.
 

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