Is the Plastic Ball's Charge Positive or Negative in a Uniform Electric Field?

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Homework Help Overview

The discussion revolves around a 2g plastic ball suspended in a uniform electric field of 1.0 x 10^4 N/C. Participants are exploring the nature of the ball's charge and its equilibrium state when the string makes a 15-degree angle with the vertical.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the charge of the ball, with one asserting it is positive. They also examine the forces acting on the ball, questioning how the angle of the string relates to the forces involved. Some suggest using the tangent of the angle to relate the electrostatic force and the weight of the ball.

Discussion Status

The discussion is active, with participants attempting to clarify the relationships between the forces and the angle. There is no explicit consensus on the correct approach, but several lines of reasoning are being explored regarding the equilibrium condition.

Contextual Notes

Participants express confusion about the problem setup and the calculations involved, indicating a need for further clarification on the relationships between the forces acting on the ball.

redhawks
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Homework Statement


A 2g plastic ball is suspended by a 2cm string in a uniform electric field of 1.0 x 10^4 N/C (the arrows point to the right)

a) is the balls charge positive of negative?
(B) If the ball is in equilibrium when the string makes a 15 degree angle with the vertical, what is the net charge. (15 degree angle going towards where the E arrows point)


Homework Equations


E=Ck((q1*q2)/r^2)

The Attempt at a Solution


a) i know it is positive
b) i did work but i can never get the right answer which is 5.3*10^-7C
 
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I'm not sure which direction your suspended object is going, but for b) consider the angle of the string. Won't it be the sum of m*g down and the electrostatic force horizontally? So isn't tan15 then the ratio of the 2 forces?
 
its going right
 
i don't understand. help, pleaseee
 
redhawks said:
i don't understand. help, pleaseee

So isn't tan15 then the ratio of the 2 forces?

F = q*E

and

q*E/(m*g) = tan15

q = m*g*tan15/E

Isn't that all there is to it?
 
redhawks said:
i don't understand. help, pleaseee

The force on the charged ball due to electric field is Eq, and weight of the ball is mg. The ratio of the forces is Eq/mg = tanθ. Solve for q.
 

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