Is the set of bounded signals considered in topology and C^1 functions compact?

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I am considering the set of all bounded signals given by

X = \left\{ x:\ |x(t)| \leq X_{\max}, \forall t \right\}.

Is this set compact? Can anyone help me?

Thank you guys
 
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symv said:
I am considering the set of all bounded signals given by

X = \left\{ x:\ |x(t)| \leq X_{\max}, \forall t \right\}.

Is this set compact? Can anyone help me?

Thank you guys



No, bounded alone does not imply compact
(in the topology of uniform convergence).
 
in what topology, in what space of functions ?
 
g_edgar said:
in what topology, in what space of functions ?


He said signals, so I guess it's something like periodic functions
that are a.e. C^1.
 
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