Is the Set of Polynomials of Degree ≤ 6 with a3 = 3 a Vector Space?

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Homework Help Overview

The discussion revolves around determining whether the set of polynomials of degree ≤ 6 with the condition a3 = 3 constitutes a vector space. Participants are exploring the implications of this specific condition on the properties of vector spaces.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the closure properties of the set under addition and scalar multiplication, questioning whether the condition a3 = 3 allows for these operations to yield results that remain within the set.

Discussion Status

Some participants have identified potential issues related to closure, particularly regarding the inability to manipulate the coefficient of x^3 while maintaining the condition a3 = 3. The discussion is ongoing, with participants considering the implications of these observations.

Contextual Notes

There is an emphasis on verifying the requirements for a vector space and understanding the constraints imposed by the specific condition on the polynomials.

kq6up
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Homework Statement



For each of the following sets, either verify (as in Example 1) that it is a vector space, or show which requirements are not satisfied. If it is a vector space, find a basis and the dimension of the space.

6. Polynomials of degree ≤ 6 with a3 = 3.

Homework Equations



N/A

The Attempt at a Solution



I put that it was a vector space with the basis of {1,x,x^2,3*x^3,x^4,x^5,x^6} and dimension of 7. I am not sure why it fails to be a vector space.

Chris
 
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What happens if you add two members of the given set, or if you multiply a member by a scalar?
 
I think there is a closure problem because one would not be able to get rid of the 3*x^3 by playing with coefficients.

I will have to think about it a little more.

Chris
 
kq6up said:
I think there is a closure problem ##\ldots##
Definitely.
 
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