Is the Strut a Two Force Member? Why is Only One Force Used in Calculations?

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SUMMARY

The discussion clarifies that a strut is classified as a two-force member, which implies that it experiences forces only at its two endpoints. The confusion arises regarding the absence of an equal and opposite force at point B (Fba) in calculations. It is established that Fba is indeed present but is considered an internal force and is not included in the free body diagram for the entire system, which consists of the bed contents and the strut.

PREREQUISITES
  • Understanding of two-force member theory in statics
  • Familiarity with free body diagrams
  • Basic knowledge of internal and external forces
  • Concept of equilibrium in structural analysis
NEXT STEPS
  • Study the principles of two-force members in structural mechanics
  • Learn how to construct free body diagrams for complex systems
  • Explore the concept of internal forces in static equilibrium
  • Review examples of strut applications in engineering problems
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Students in engineering mechanics, structural engineers, and anyone studying statics and dynamics of structures will benefit from this discussion.

xzibition8612
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The Attempt at a Solution


The book says the strut is a two force member. Why then isn't there a equal but opposite direction force Fba at point B? Isn't that what a two force member means? Why for this two-force member only the force at point A is used in the calculations? Thanks.
 

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hi xzibition8612! :smile:
xzibition8612 said:
The book says the strut is a two force member. Why then isn't there a equal but opposite direction force Fba at point B?

there is

but the free body diagram is for the whole thing (bed contents and strut),

so Fba is not used since it's an internal force :wink:
 
damn your smart
 

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