Is there a lower limit to the separation between capacitor plates?

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SUMMARY

The discussion centers on the behavior of parallel plate capacitors as the separation distance (d) between the plates decreases, particularly at around 10 microns. It establishes that as the plates are brought closer, losses due to equivalent series resistance (ESR) increase, potentially leading to a scenario where the capacitor behaves more like a resistor. Key factors influencing this behavior include electron flow between plates, dielectric relaxation, and the dielectric strength, which is approximately 1V/micron for air. Tunneling conduction may also occur at sub-micron distances, further complicating the capacitor's performance.

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  • Understanding of parallel plate capacitor design
  • Knowledge of equivalent series resistance (ESR) in capacitors
  • Familiarity with dielectric materials and their properties
  • Concept of dielectric strength and breakdown voltage
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theman2000
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Let's say I build a parallel plate capacitor using two metal plates with perfectly smooth surfaces. They are separated by some small distance d, with only vacuum between them. I then apply some AC voltage across the plates. Is there some effect which causes loss in the capacitor (equivalent series resistance) that increases as the plates are moved closer and closer together (as d decreases)? More practically, we're talking about d on the order of ~10 microns or so. At some point will the loss become so high that the capacitor will become more of a resistor than a capacitor?
 
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theman2000 said:
Let's say I build a parallel plate capacitor using two metal plates with perfectly smooth surfaces. They are separated by some small distance d, with only vacuum between them. I then apply some AC voltage across the plates. Is there some effect which causes loss in the capacitor (equivalent series resistance) that increases as the plates are moved closer and closer together (as d decreases)? More practically, we're talking about d on the order of ~10 microns or so. At some point will the loss become so high that the capacitor will become more of a resistor than a capacitor?
The loss is firstly in the metal itself, by its resistance. A capacitor does not have loss in terms or electric resistance between the plates. However, if you bring those plates close enough, very little voltage is required to let the electrons start to jump from one plate to the other. Then you will have an electron flow between the plates which can be seen as a loss pretty much as in a resistor as not all electric current is flowing through the generator, but also through the capacitor. If you heat the plates you will increase the electron flow - just like inside a radio tube, but also reduce the electric resistance.
 
There is energy lost in the dielectric, due to dielectric relaxation and/or residual conduction. It is measured by the angle of loss (or dissipation angle). It may be represented or modeled by a resistor in series with the ideal capacitor. The angle of loss is defined by
tan(delta)=R/X where R is this equivalent resistance and X is the reactance of the capacitor.
However, I expect that the factor that determines the minimum distance (for a given nominal voltage) is the dielectric strength or breakdown field.
For air is about 10^6 V/m so this will be about 1V/micron. However for this layers the strength may change. For sub-micron dielectric layers tunneling conduction may occur.
 

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