Is There an Easier Way to Solve this Definite Integral?

Click For Summary
SUMMARY

The integral ∫_(-∞)^∞ x^2 e^(-λ(x-a)^2) dx, where λ and a are positive real constants, can be effectively solved using differentiation of the Gaussian integral with respect to λ. The initial attempts at integration by parts and y-substitution did not yield results. The correct approach involves recognizing the integral's relation to Gaussian integrals and applying differentiation techniques to simplify the process. Utilizing a table of integrals may also assist in finding the solution.

PREREQUISITES
  • Understanding of Gaussian integrals
  • Familiarity with integration techniques such as integration by parts
  • Knowledge of substitution methods in calculus
  • Basic concepts of definite integrals
NEXT STEPS
  • Study the properties of Gaussian integrals and their applications
  • Learn how to differentiate integrals with respect to parameters
  • Explore advanced integration techniques, including y-substitution
  • Review integral tables for common forms and solutions
USEFUL FOR

Students in physics or mathematics, particularly those tackling advanced calculus problems involving definite integrals and Gaussian functions.

simo
Messages
18
Reaction score
0

Homework Statement



solve the integral: ∫_(-∞)^∞▒〖x^2 e^(-λ(x-a)^2 ) 〗 dx
where λ and a are positive real constants


The Attempt at a Solution



I tried integration by parts with and without y-substitution but neither worked for me.

Without substitution, I set up the integral to look like:
∫_(-∞)^∞▒〖xe^(-λx^2 )•xe^λa(2x-a) 〗 dx

u=xe^λa(2x-a) and dv=xe^(-λx^2 ) dx

after doing this a few times I realized it wouldn't work.

For y-substitution I used y = x-a. ∫_(-∞)^∞▒〖(y+a)^2 e^(-λ(y)^2 ) 〗
I then tried to integrate this by parts with u=(y+a)^2 and dv=e^(-λy^2 )
 
Physics news on Phys.org
I assume you want to solve
\int_{-\infty}^{\infty} x^2 e^{-\lambda (x - a)^2 } \, dx

In that case, try differentiation of an ordinary Gaussian integral w.r.t \lambda (twice).
 
Yea, I didn't have it in the right form. It's for a physics class, so the books says to use a table to help. I think I will try to solve it out anyway. Thanks for the help.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 105 ·
4
Replies
105
Views
7K
  • · Replies 22 ·
Replies
22
Views
3K
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K