looka said:
I would think so also. As shiny and radiating our Sun is, it is still a great amount of mass that really shield us from every imaginable radiation comming from deep space, from that direction that is.
Quibble: a "shield" that covers a bit over half a degree of angular size is not shielding "us" from much!
For the Sun to appear black, you'd have to be observing a background of some kind, or using a very long exposure. I'd be surprised to see an image where this occurs. There is, of course, the deliberate use of shields in some image specifically to block out the Sun. See, for example, this Astronomy Picture of the Day for October 29 2003, of a solar flare. (The image is a link to the APOD website)
More relevant for shielding the Earth are the Sun's magnetic fields, which divert charged particles like cosmic rays. From
High Energy Cosmic Rays and the Sun at SLAC, Stanford:
The sun does, however, also have an effect on high-energy cosmic rays. High-energy cosmic rays come from interstellar space and are sometimes called Galactic Cosmic Rays (GCRs), even though it is thought that some of them come from beyond our galaxy. The solar wind mentioned above consists of a continuous stream of plasma, loose protons and electrons. The region of space in which the influence of the solar wind is felt, called the heliosphere, extends far beyond the orbit of Pluto. Because the solar wind is a plasma, it is electrically conducting and transmits a part of the sun's magnetic field. When GCRs approach the sun they encounter the heliosphere and the magnetic field within it. Because of the shape of the magnetic field, the GCRs lose some of their energy, and the lower-energy ones never reach the vicinity of the earth. In times of high solar activity (high levels of solar wind) this effect is stronger and fewer GCRs reach the earth.
This is not a case of the Sun itself being the shield, however, and would not make the Sun appear as a black disk in an image.
Cheers -- sylas