Is this a correct way to rewrite the binomial theorem?

AI Thread Summary
The discussion focuses on the correct rewriting of the binomial theorem, specifically extracting the first term from the summation. The proposed rewrite, (a+b)^n = {n choose 0}a^n + ∑_{k=1}^{n}{n choose k} a^{n-k} b^k, is confirmed as valid. Participants also verify another expression involving sigma notation, concluding that both transformations are correct. The conversation highlights the importance of understanding sigma notation in manipulating binomial expansions. Overall, the participants successfully clarify their queries regarding the binomial theorem.
jey1234
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Homework Statement


I am doing a poof and I need to use the binomial theorem. However is the following a correct way to rewrite it?

(a+b)^n\ =\ {n \choose 0}a^{n} + \sum_{k=1}^{n}{n \choose k}\ a^{n-k}\ b^{k}

Homework Equations



(a+b)^n\ =\ \sum_{k=0}^{n}{n \choose k}\ a^{n-k}\ b^{k}

The Attempt at a Solution


Basically, I want to extract the first term of the binomial expansion out of the summation but I'm not that good with sigma notation. Don't I just have to increase the lower bound by 1 and write the first term outside (as shown above)? Thanks.
 
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hey jey1234! :wink:

yes, that's fine :smile:
 
thanks tim. one more quick question. is the following correct?

\frac{1}{a}\sum_{k=1}^{n}a^{k}\ b^{k}\ =\ \sum_{k=1}^{n}a^{k-1}\ b^{k}
 
jey1234 said:
thanks tim. one more quick question. is the following correct?

\frac{1}{a}\sum_{k=1}^{n}a^{k}\ b^{k}\ =\ \sum_{k=1}^{n}a^{k-1}\ b^{k}
Yes, that's correct.
 
thanks sammy :smile:
 
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