Is this a simultaneous equation question?

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Homework Statement
A rectangle has height h and base b
The area of the rectangle is 54cm^2
The perimeter of the rectangle is 33cm
h=54/b

Work out the height and base of the rectangle
Relevant Equations
A=hb
P=2h+2b
hb=54
2h+2b=33
h=54/b

therefore,

2(54/b)+b=33
108/b + b = 33

I’ve got a feeling I’ve gone down a blind alley here.
Any hints?
 
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One thing to make a mental note of (and nevr forget) is that an equation of the form:$$x + \frac a x + c = 0$$is a quadratic equation in disguise!
 
paulb203 said:
I’ve got a feeling I’ve gone down a blind alley here.
Any hints?
Multiply both sides by b.
 
paulb203 said:
2(54/b)+b=33
This equation is mistaken.
 
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