Speed of Reflected Light on a Rotating Plane Mirror

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SUMMARY

The speed of the spot of light moving across a screen from a rotating plane mirror can be calculated using the mirror's angular velocity and the distance to the screen. Given that the mirror rotates at 30 revolutions per minute, the angular velocity is 3.14 radians per second. By multiplying this angular velocity by the distance of 20 meters, the endpoint velocity is determined to be 62.83 meters per second. The speed of the light spot on the screen is twice this value, resulting in a final speed of 125.66 meters per second.

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A horizontal beam of light is reflected from a plane mirror that revolves about a vertical axis at a rate of 30 rev/min. The reflected beam sweeps across a screen that, at the point nearest the mirror, is 20 m away. With what speed does the spot of light move across the screen at the point nearest the mirror?

Is it c? (3*10^8)
I know I am not understanding. Can someone explain this one to me? I am not even sure where to start.
 
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The angular velocity of the mirror is 30*2*Pi/60 radians per second. Multiply this by 20 meters to get the velocity (in meters per second) of the endpoint of a rod which is 20 meters long and perpendicular to the mirror. The speed of the spot of light will be twice that, that is, if I understood the problem correctly. Note that when the mirror (along with the imaginary attached rod) turns by 45 degrees, the reflected ray turns by 90 degrees, i.e. 2*45 degrees.
 
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Always start by drawing a diagram!
Make sure the quantity you want (distance along screen) is on the diagram!
 

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