Undergrad Is this answer about Lorentz transforms correct?

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User Jack Fraser's assertion that both ##X## and ##\Lambda## are tensors is incorrect; only ##X## qualifies as a tensor. The Lorentz transformation is a matrix that relates tensor components between different coordinate systems, while ##\Lambda## does not transform as a tensor. The discussion highlights that coordinates, represented by ##X##, do not generally transform using the Lorentz transformation matrix ##\Lambda^{\mu'}{}_\mu X^\mu##. Instead, the transformation involves defining vectors associated with coordinates and transforming those vectors. The conclusion emphasizes that treating ##X## as a generic vector is acceptable, but interpreting it strictly as coordinates requires additional assumptions.
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##X## is, ##\Lambda## is not.

Thinking in terms of components, the components of a tensor multiply the outer product of the basis vectors or one-forms, and the sum of the components times those basis entities forms the geometric object that is the tensor. The Lorentz transform is just a matrix of numbers that relate tensor components in one coordinate system to tensor components in another.
 
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How would a coordinate transformation transform under a coordinate transformation?
 
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Ibix said:
##X## is, ##\Lambda## is not.
I think neither of them are tensors. The referred user talks about coordinate transformation, so his ##X## are coordinates.
haushofer said:
How would a coordinate transformation transform under a coordinate transformation?
no way :biggrin:
 
kent davidge said:
I think neither of them are tensors. The referred user talks about coordinate transformation, so his ##X## are coordinates.
But coordinates do not, in general, transform by ##\Lambda^{\mu'}{}_\mu X^\mu##. He can get away with it in Einstein coordinates on flat spacetime because there's a trivial relationship between the coordinates and a set of "position vectors" defined in the tangent space associated with the origin.

So what he's doing is not - strictly - transforming coordinates. He's defining a set of vectors, associating them with the coordinates, transforming the vectors, and associating them with the transformed coordinates.

Treating ##X## as any generic vector is fine and my previous answer stands. If you want to interpret ##X## as coordinates then you need to make additional assumptions.
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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