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## Main Question or Discussion Point

Question : General solution of dy/dt = -ay + b

My solution :

dy/dt = -a(y-b/a)

(dy/dt)/(y-(b/a)) = -a

ln | y-(b/a) | = -at + C

e

Ce

My solution :

dy/dt = -a(y-b/a)

(dy/dt)/(y-(b/a)) = -a

**Integrating both sides :**ln | y-(b/a) | = -at + C

e

^{(-at+C)}= y-(b/a)Ce

^{(-at)}= y-(b/a)