- #1
xavier777
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Question : General solution of dy/dt = -ay + b
My solution :
dy/dt = -a(y-b/a)
(dy/dt)/(y-(b/a)) = -a
Integrating both sides :
ln | y-(b/a) | = -at + C
e^{(-at+C)} = y-(b/a)
Ce^{(-at)} = y-(b/a)
My solution :
dy/dt = -a(y-b/a)
(dy/dt)/(y-(b/a)) = -a
Integrating both sides :
ln | y-(b/a) | = -at + C
e^{(-at+C)} = y-(b/a)
Ce^{(-at)} = y-(b/a)