Is this statement for proving inequalities true?

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To prove the inequality a < b using the known inequalities a > c and c < b, one cannot directly conclude that a < b. The discussion highlights the incorrect assumption that c < a and c < b necessarily imply a < b. A counterexample is suggested to illustrate this flaw in reasoning. The original poster acknowledges their mistake in understanding the implications of the inequalities. The conversation emphasizes the importance of careful reasoning in mathematical proofs.
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Hello! What I'm wondering is if you want to prove an inequality, let's say ##a<b## and you already know that ##a>c## is true. If you are able to prove that ##c<b## is true, would that go on to imply that ##a<b## is true also? If this is correct, is it known as a theorem?

Thank you!
 
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No. Can you find a counterexample?
 
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Physicist97 said:
Hello! What I'm wondering is if you want to prove an inequality, let's say ##a<b## and you already know that ##a>c## is true. If you are able to prove that ##c<b## is true, would that go on to imply that ##a<b## is true also? If this is correct, is it known as a theorem?

Thank you!

In other words:

##c < a## and ##c < b## implies ##a < b##

There's something not right there.
 
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Mhmm, yea I see where I went wrong haha. It was a pretty silly mistake, too :). Thank you everyone.
 
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