Is this statement for proving inequalities true?

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The discussion centers on the validity of the statement that if \( a > c \) and \( c < b \), then \( a < b \) must also be true. Participants clarify that this implication is incorrect and emphasize the need for a counterexample to demonstrate the flaw in reasoning. The conclusion drawn is that the relationship does not hold universally, and the initial assumption is a common misconception in inequality proofs.

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Physicist97
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Hello! What I'm wondering is if you want to prove an inequality, let's say ##a<b## and you already know that ##a>c## is true. If you are able to prove that ##c<b## is true, would that go on to imply that ##a<b## is true also? If this is correct, is it known as a theorem?

Thank you!
 
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No. Can you find a counterexample?
 
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Physicist97 said:
Hello! What I'm wondering is if you want to prove an inequality, let's say ##a<b## and you already know that ##a>c## is true. If you are able to prove that ##c<b## is true, would that go on to imply that ##a<b## is true also? If this is correct, is it known as a theorem?

Thank you!

In other words:

##c < a## and ##c < b## implies ##a < b##

There's something not right there.
 
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Mhmm, yea I see where I went wrong haha. It was a pretty silly mistake, too :). Thank you everyone.
 

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