Is this the correct way to find the antiderivatives?

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    Antiderivatives
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SUMMARY

The correct method for finding the antiderivative of the function ∫ (v^2 - e^(3v)) dv involves separating the integral into two parts: ∫(v^2)dv and ∫(e^(3v))dv. The proper antiderivative is (1/3)v^3 - (1/3)e^(3v) + C, where C represents the constant of integration. It is essential to eliminate the integral sign after antidifferentiation and to use the equals sign to connect equivalent expressions.

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rowdy3
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Find the following.
∫ (v^2 - e^(3v)) dv.
I did
∫(V^2-e^(3v)) dv
∫(v^2)dv - I (e^(3v) )dv
∫(v^3)/3- (e^(3v))/3
∫(v^3-e^(3v))/3
Did I so it right?
 
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rowdy3 said:
Find the following.
∫ (v^2 - e^(3v)) dv.
I did
∫(V^2-e^(3v)) dv
∫(v^2)dv - I (e^(3v) )dv
∫(v^3)/3- (e^(3v))/3
∫(v^3-e^(3v))/3
Did I so it right?

Not quite. After you antidifferentiate the integral sign should be gone. Also, you need to include the constant of integration and you should use = to connect expressions that are equal.

∫(v^2-e^(3v)) dv
= ∫(v^2)dv - ∫ (e^(3v) )dv
= (v^3)/3- (e^(3v))/3 + C

This could also be written as
(1/3)v3 - (1/3)e3v + C
or as (1/3)(v3 - e3v) + C
 

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