Is this the correct way to find the antiderivatives?

[rowdy3]

Find the following.
∫ (v^2 - e^(3v)) dv.
I did
∫(V^2-e^(3v)) dv
∫(v^2)dv - I (e^(3v) )dv
∫(v^3)/3- (e^(3v))/3
∫(v^3-e^(3v))/3
Did I so it right?

 

[Mark44]

Find the following.
∫ (v^2 - e^(3v)) dv.
I did
∫(V^2-e^(3v)) dv
∫(v^2)dv - I (e^(3v) )dv
∫(v^3)/3- (e^(3v))/3
∫(v^3-e^(3v))/3
Did I so it right?

Not quite. After you antidifferentiate the integral sign should be gone. Also, you need to include the constant of integration and you should use = to connect expressions that are equal.

∫(v^2-e^(3v)) dv
= ∫(v^2)dv - ∫ (e^(3v) )dv
= (v^3)/3- (e^(3v))/3 + C

This could also be written as
(1/3)v³ - (1/3)e^3v + C
or as (1/3)(v³ - e^3v) + C