Isentropic Specific Enthelpy HELP

  • Context: Graduate 
  • Thread starter Thread starter bobboviking
  • Start date Start date
  • Tags Tags
    Isentropic Specific
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 6K views
bobboviking
Messages
5
Reaction score
0
Hi guys,

I'm struggling with some equations regarding the enthalpy change over a compressor in a vcc system.

I'm currently working on a model for the whole system and I think I've got all equations except the one describing the enthalpy difference betweeen the inlet and outlet of the compressor.
I can't really understand how to handle the isentropic specific enthalpy, hout,s, in the following equation:

hout = (hout,s - hin)/ns + hin

where ns is the isentropic efficiency

I also know that ns = (Tout,s-Tin)/(Tout-Tin) (assuming constant specific heat)

I would prefer the model to be as "general" as possible, meaning that I don't have to perform a bunch of experimental test to determine certain coefficients.

I would greatly appreciate some help with how to calculate/estimate hout,s. I think that the value of hout,s depends on the suction pressure (?) so assuming a constant value (from example a table at some operating condition) isn't good enough for an accurate model? I mean that value of hout,s does change when the system moves from that particular condition, right?

Thanks in advance,
Andreas
 
Last edited:
Physics news on Phys.org
To get the isentropic enthalpy out, you start with the inlet conditions of temperature and pressure and determine from the tables the entropy in. You must have already don this since you seem to know hin. Then you look up in your tables the enthalpy at the outlet pressure and at the same entropy as inlet. Simple as that. This is hout,s.