Ising Model for Spins: External Magnetic Field Effect

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The discussion centers on the Ising Model for spins in the presence of an external magnetic field, specifically addressing the Hamiltonian formulation: H = -J ∑S_iz * S_jz + ∑ S_iz * B. The participants explore the implications of applying the mean-field approximation to the Ising term when an external magnetic field is present. It is established that the average spin is influenced by the external field, complicating the assumption that deviations from the average remain small. The conversation highlights the necessity of considering different mean fields for varying Hamiltonians, particularly under strong external influences.

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I think most of you are familiar with this model (sum runs over nearest neighbours):

H = -J ∑S_iz * S_jz

It demonstrates one of the succeses of meanfield theory as one can succesfully introduce:

S_iz = <S_iz> + S_iz - <S_iz> = <S_iz> + δS_iz

Such that:

S_iz*S_jz ≈ 2S_iz<S_jz> + const

Where I have neglected the second order term. Now my question:
In the presence of an external magnetic field the Hamiltonian gets introduced a second term which couples the spins to the external magnetic field:

H=H_ising + ∑ S_iz * B

In this case can I still use the mean-field approximation separately for the Ising term? My book certainly does it, but I am a bit confused because in my head the average <S_iz> is affected by the external magnetic field's effect on the spin, and in this case it is not for me obvious that just because the deviation from the average is small in the case of no external field, it should be too in the presence of one.
 
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The average \langle S_j^z \rangle is certainly changed by the external magnetic field - consider the extreme case with an antiferromagnetic J and a strong field along some axis. This will change the mean field from zero in the case of no field to its maximal value in the case of a strong field. There are different mean fields for different Hamiltonians, if you will.
 

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