What is the Period of Oscillation Based on Given Coordinates?

[whitetiger]

Homework Statement

Now assume that the x coordinate of point R is 0.12m and the t coordinate of point K is 0.0050 s.

What is the period T ?

Homework Equations

T = 1/f where f is the frequency and T is the period.

The Attempt at a Solution

From the graph, there are 2 periods in oscillation. So I guess that the period would be 2T and since it starts at R = .12m and reaches point K in .0050 s . So the velocity is .12m/.0050 s = 24m/s

Not sure if this is correct but, T = 2T = .12m/.005s = T = 12 s

 

[berkeman]

No. The horizontal distance from 0 to K is a quarter of the period of that sinusoidal waveform. Since you are given the time difference from 0 to K, and that is a quarter of the period, what is the total period?

 

[whitetiger]

No. The horizontal distance from 0 to K is a quarter of the period of that sinusoidal waveform. Since you are given the time difference from 0 to K, and that is a quarter of the period, what is the total period?

Thank for the help

From what you have said, I can calculate the total period to be (.005)4 = .02s

 

[berkeman]

Good. Quiz Question -- what is special about that period?