I've done 95% of this. I just don't get one specific part. General cal physics

AI Thread Summary
The discussion revolves around a physics problem involving a fish's movement in relation to a rock's position. The participant has successfully solved parts of the problem but is confused about incorporating the rock's position into their calculations for the final position at 25 seconds. They note that their previous calculations did not require the rock's position, yet the solution provided in the textbook includes it. The main inquiry is about understanding when to include reference points like the rock in similar problems. The consensus suggests focusing on vector components and understanding the relationship between initial position and final displacement.
randoreds
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Homework Statement


A fish is swimming in a horizontal place has velocity of ( vi = 4.00i + 1.00j) ms at a point in the ocean where the position relative to a certain rock is ri=(10.i- 4.00j)m. After the fish swims with constant acceleration for 20 s, it velocity is v = 20.0i -5.00j. Question C) what is the position at 25 s, if at a constant velocity.

Homework Equations


Δd= vit+ 1/2at^2

The Attempt at a Solution

Ok part a) so the components of V are .79 in the X direction and -0.3 in the Y direction. part b) was you had to find the direction of the vector with respect to the x-axis it is 339degree sign. But for part C, I'm solving for Xf and Yf.
Xf = (4.00) (25) + (1/2) (.79)(25)^2 (-- This is wrong. I checked the solution in the back. and the only difference is 10. I think it has to do with the rock. for some reason they randomly added the position of the Rock. So my question is why? Because when I was solving for the components(part A), I didn't need to add the position of the rock. And I got the right answer! Any help would be appreciated
 
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And my question is more, how would you know to do this? (if I encounter this doing other problems)
 
randoreds said:

Homework Statement


A fish is swimming in a horizontal place has velocity of ( vi = 4.00i + 1.00j) ms at a point in the ocean where the position relative to a certain rock is ri=(10.i- 4.00j)m. After the fish swims with constant acceleration for 20 s, it velocity is v = 20.0i -5.00j. Question C) what is the position at 25 s, if at a constant velocity.

Homework Equations


Δd= vit+ 1/2at^2

The Attempt at a Solution

Ok part a) so the components of V are .79 in the X direction and -0.3 in the Y direction. part b) was you had to find the direction of the vector with respect to the x-axis it is 339degree sign. But for part C, I'm solving for Xf and Yf.
Xf = (4.00) (25) + (1/2) (.79)(25)^2 (-- This is wrong. I checked the solution in the back. and the only difference is 10. I think it has to do with the rock. for some reason they randomly added the position of the Rock. So my question is why? Because when I was solving for the components(part A), I didn't need to add the position of the rock. And I got the right answer! Any help would be appreciated

More likely you will need to use just vectors for the equation to determine the answer. Don't find the diagonal components yet!
 
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