[Javascript?] Using a function as an argument for another function

mindauggas · Sep 19, 2012

Code (Text):

var square = function (x) {
return x * x;
};

var cube = function (x) {
return square * x;
};

This is my shot, its not right. Please indicate or suggest the correct answear. :)

Mark44 · Sep 19, 2012

Re: Using a function as an argument for another function

mindauggas said: ↑

Code (Text):

var square = function (x) {
return x * x;
};

var cube = function (x) {
return square * x;
};

This is my shot, its not right. Please indicate or suggest the correct answear. :)

No, it's not correct.

Code (Text):

var cube = function (x) {
return x * square(x);
};

Your thread title is misleading - you aren't using a function as an argument of another function. One function is calling another function. There's a difference.

rcgldr · Sep 19, 2012

Re: Using a function as an argument for another function

In C or C++, you can use pointers to functions as arguments:

Code (Text):

#include <stdio.h>

int f1xf2(int (*pf1)(int), int (*pf2)(int), int v){return(pf1(v) * pf2(v));}
int returnv(int v){return(v);};
int square(int v){return(f1xf2(returnv, returnv, v));}
int cube(int v){return(f1xf2(returnv, square, v));}
int quad(int v){return(f1xf2(square, square, v));}

int main(int argc, char ** argv)
{
printf("square 2 = %3d\n", square(2));
printf("cube 3 = %3d\n", cube(3));
printf("quad 4 = %3d\n", quad(4));
return(0);
}

gsal · Sep 19, 2012

Re: Using a function as an argument for another function

I am confused...it always bugs me when people do not state what language they are talking about...sure, if I knew, I would recognize it; but often times I don't and I can still help, if I knew what to google.

So, the last post is C, sure...what's the first one, too? or is it matlab?

Mark44 · Sep 20, 2012

Re: Using a function as an argument for another function

Looks like JavaScript to me.

mindauggas · Sep 21, 2012

Sorry, it's JavaScript

mindauggas · Sep 24, 2012

Once again, sorry. This time for abandoning my own topic. Like I said the programming language is JavaScript. And yes, thanks for pointing out, that the title is misleading: the function is indeed calling another function, not using it as an argument.

Returning to the problem. "When we call the square function as a part of the cube function, we still have to define the parameter associated with the square function" - a hint provided says thus. But how to write this assignment? I have never assigned a parameter for a function in the body of another function.

Any hints?
Should I assign a parameter the same way as a variable?

gsal · Sep 24, 2012

These kind of simple questions is something you don't need a forum for...you can play around with the language and its compiler/interpreter and test stuff at will...it does not cost any money and you are not going to break anything...play around, experiment!

...if, on the other hand, you have a major logic problem or a bug that you cannot find...then, the forum could help.

gabbagabbahey · Sep 24, 2012

mindauggas said: ↑

Returning to the problem. "When we call the square function as a part of the cube function, we still have to define the parameter associated with the square function" - a hint provided says thus. But how to write this assignment? I have never assigned a parameter for a function in the body of another function.

Any hints?
Should I assign a parameter the same way as a variable?

Can you state the original problem/assignment as it is given to you?

DavidSnider · Sep 24, 2012

Using a function as an argument to another function would work like this:

Code (Text):

var square = function(x) { return x * x; }
var cube = function(f,x) { return x * f(x); }

cube(square,2);

Though in this context I don't know why you'd want to pass in a function. I don't imagine you'd ever be swapping it out.

mindauggas · Sep 24, 2012

DavidSnider said: ↑

Using a function as an argument to another function would work like this:

Code (Text):

var square = function(x) { return x * x; }
var cube = function(f,x) { return x * f(x); }

cube(square,2);

Though in this context I don't know why you'd want to pass in a function. I don't imagine you'd ever be swapping it out.

Thanks, this solved it.

Code (Text):

var square = function (x) {
return x * x;
};

var cube = function (x) {
return square(x) * x;
};

The answer to your question: it just for the sake of knowing how to use functions in all/allmost alt the ways legitimate.

rcgldr · Sep 24, 2012

I thought the idea was to use functions as parameters to other functions. I'm not sure if this syntax is correct for javascript, but it should look something like this:

Code (Text):

var f1xf2 = function(f1, f2, x) {return f1(x) * f2(x);}
var returnx = function(x) {return x;}
var square = function(x) {return x * x;}
var cube = function(x) {return f1xf2(returnx, square, x);}

mindauggas · Sep 25, 2012

rcgldr said: ↑

I thought the idea was to use functions as parameters to other functions. I'm not sure if this syntax is correct for javascript, but it should look something like this:

Code (Text):

var f1xf2 = function(f1, f2, x) {return f1(x) * f2(x);}
var returnx = function(x) {return x;}
var square = function(x) {return x * x;}
var cube = function(x) {return f1xf2(returnx, square, x);}

The original title probably mislead you, I apologize for this. the title should have stated that one function calls another function :)

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[Javascript?] Using a function as an argument for another function

mindauggas

Mark44

Staff: Mentor

rcgldr

gsal

Mark44

Staff: Mentor

mindauggas

mindauggas

gsal

gabbagabbahey

DavidSnider

mindauggas

rcgldr

mindauggas

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